Theorem
A connected set cannot be expressed as the union of nonempty, disjoint, closed subsets.
Proof
Supposeis connected and closed sets
exist with
Thenand
The complement of a closed set is open, so thatand
are also both open and
is the union of open sets
and
Hence
is not connected.
Conversely supposeis disconnected. Then nonempty open sets
exist such tha
and
Thenand
so that
and
are closed - a contradiction.