Theorem
Any countably compact metric space
is separable.
Proof
Let
be any positive number. There is a maximal subset
such that for![]()
Suppose
is infinite for some
then
has an accumulation point![]()
contains infinitely many points of
All points in
are a distance less than
from
so
contains infinitely many points of
This is a contradiction and
is finite for each![]()
Then for any![]()
else contradicting the maximality of![]()
For each positive integer n define
then
is a countable dense subset of
and
is separable.