Theorem
Let
be a family of topologies on a set
and let
be continuous with respect to each topology![]()
Then
is continuous with respect to
Since the indiscrete topology is the intersection of every topology on![]()
is continuous with respect to the indiscrete topology.
Proof
The intersection of any topology is itself a topology.
Let
be any open subset of
so that
Consider
Since
is continuous with respect to each topology
the set
belongs to each
hence
![]()
Hence
is continuous with respect to![]()