Theorem
A function
defined on a first countable space
is continuous at a point
if and only if it is sequentially continuous at the point.
Proof
Let
be a function on a set
nd let
be a nested local base at![]()
Suppose
is not continuous. Then an open set
exists such that
and for every![]()
![]()
Thus for every
an
exists such that
so![]()
Hence
but![]()