Theorem
Let
be a compact subset of a Hausdorff space
If a in X-A then open sets U and V exist such that
and![]()
Proof
Choose
Since
and since
is Hausdorff, open sets
and
exist such that
and![]()

Since A is compact, a finite subcover
exists such that![]()
Define
and![]()
and
are open, and
and![]()
![]()
But since
for
we have![]()