Theorem
Let
be a Cauchy sequence in a metric space
and let
be a subsequence.
Then
as![]()
Proof
Let
Since
is Cauchy, there exists
such that![]()
But
and![]()
Hence
as![]()
Theorem
Let
be a Cauchy sequence in a metric space
and let
be a subsequence.
Then
as![]()
Proof
Let
Since
is Cauchy, there exists
such that![]()
But
and![]()
Hence
as![]()