Theorem
Every element of a set
is the discrete topology if and only if every point of
is an open set.
Proof
If
is the discrete topology then every element of
is an open set so that![]()
This shows that if
is the discrete topology every point of
is an open set in![]()
Conversely suppose that every element of
is an open set
Since
is a topology it contains every union of elements of
so that if
then
Since this is true for all n and x, every collection of points in
is an element of
so
contains all collections of points of
and is the discrete topology on![]()