Theorem
A compact metric space
is complete.
Proof
Suppose
is a countable family of closed, nonempty subsets of X such that![]()
Since
is compact,![]()
Let
be a Cauchy sequence in X.
Define![]()
![]()
![]()
and so on.
Then
and
and all the
are closed, nonempty subsets of
Hence![]()
Let
and take
then there exists
such that for![]()
Hence![]()
For all
hence![]()
Hence X is complete.