Theorem
Let
be a connected set and let
be an open cover of
Any two points of
can be joined by a simple chain consisting of elements of
.
Proof
Subsets
of
are said to form a simple chain between points
and
if
-
Only
contains
-
Only
contains
-
if
Let
and let
be the set of all points of
which are to be joined to
by a simple chain consisting of elements of![]()
Let
then there exists a simple chain
from
to
All elements of
belong to
since the chain
connects x with any element of
hence![]()
Since
is open, so is![]()
Suppose now that
Since
is a cover of
there is an element
such that![]()
Suppose
then there is some chain from
to
and
- a contradiction hence
and![]()
Hence
is open and
is closed.
We concude
and the theorem is proved.