Theorem
Let
and
be connected sets which are not mutually separated. Then
is connected.
Proof
In a topological space
are said to be mutually separated if
and![]()
Suppose
is disconnected then there exist disjoint nonempty open sets
and
such that
with
or![]()
If
and
then
and
are separated sets - a contradiction.
Thus either
or![]()
Therefore
is not a disconnection of
and
is connected.