Suppose
and
with both
and
having the natural order.
B is isomorphic under to and onto the set
with
with![]()
Both
and
have the same ordinal number,![]()
Consider the sets
and![]()
so that![]()
so that![]()
so the order of union of two sets does matter with respect to ordinal numbers.
We can also write
so it is also true that![]()
This means that ordinal numbers are not commutative under addition.