Theorem
Let
be the product space of the countable family of non - empty spaces![]()
Then
is compact if and only only each component space is compact.
Proof
Suppose
is compact. For each
the projection map
is continuous and onto.
Therefore
is compact for each![]()
Conversely suppose each
is compact. Let
be any sequence in
with the kth component of
written as
Then
is an ultranet in
and
converges in
Therefore
converges in![]()
A space
is compact if every sequence in
converges to a point in
hence
is compact.