The system with linearisation matrix given byhas eigenvalues which are the solution to
These eigenvalues are
The eigenvectors corresponding to these eigenvectors will be complex when solved using
We can however transform coordinates. When we transform to polar coordinates, the system becomes much simpler. If the eigenvalues arethen define
Similarlyand differentiation gives
Hence
We obtain the simple equationsand
We can solve these to obtainand
Elimination ofbetween these two equations gives
Ifandorandthenincreases exponentially asincreases. Ifandhave the same sign thendecreases exponentially asincreases.