Is it Possible to Construct a Triangle with an Angle of 60 Degrees and Sides in a Geometric Progression

It is possible to constrict a Right Angled Triangle With Sides in a Geometric Progression. This triangle can be scaled up to give an infinite number of triangles with sides in a geometric progression.
Is it possible to construct a triangle with a 60 degree angle with sides in a Geometric Progression? If so, then the smallest side must be opposite the smallest angle, and the largest side opposite the largest angle. We obtain the triangle below.


Applying the Cosine Rule:
\[a^2 = b^2+c^2-2 \times b \times c \times cos A\]

\[(xy)^2 = x^2+(xy^2)^2-2 \times x \times (xy^2) \times cos 60\]

\[(xy)^2 = x^2+(xy^2)^2-2x(xy^2)cos 60\]

\[x^2y^2 = x^2+x^2y^4-2x(xy^2) \times \frac{1}{2}\]

\[ x^2y^2 = x^2+x^2y^4-x^2y^2\]

\[y^2 = 1+y^4-y^2\]

\[ 0 = y^4-2y^2+1\]

\[0= (y^2-1)^2\]

All the sides are length  
  units and the triangle is isosceles, so no such triangle exists.

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