Any transformation
represented by a matrix
whose entries are numbers is linear. The matrix will send a line to a line. Sometimes it may send points on a line to some other point on the same line, and sometimes it will send a point to itself. In the second case, the point is said to be invariant.
Every transformation represented by a matrix has at least one invariant point – the origin, since if
is the matrix representing T,
where
indicates the zero vector with every entry equal to 0. Suppose that
is an invariant of
so that![]()
The above equation means that
is an eigenvector of
with eigenvalue 1. Not all matrices have such eigenvalues, so this is a condition of a transformation having invariant points other than vec 0 . If such a vector
exists, any scalar multiple of
will also be invariant since![]()
This means that the eigenvector corresponding to an eigenvalue of 1 will define a line every point of which is an invariant point.
Example:
Suppose a transformation
is represented by
The eigenvalues are the solutions to![]()
![]()
![]()
If
the eigenvectors
are the solutions to![]()
![]()
Hence
and an eigenvector is
but this is not invariant, because the eigenvalue is 3 so![]()
If
the eigenvectors
are the solutions to![]()
![]()
Hence
and an eigenvector is
but this is invariant, because the eigenvalue is 1 so![]()
Also, any scalar multiple of
is invariant so in particular
which defines the line
is invariant.