\[0.454g=0.454 \times 9.8\]
\[Pressure= 45 \times \frac{Force}{Area}= \frac{0.454 \times 9.8}{(2.54 \times 10^{-2})^2}=3.10 \times 10^5 Pa\]
.Suppose, when someone is sitting on the bike, that the tyres have an area of
\[10 cm^2 =10^{-3} m^2\]
.If the person sitting on the bike has a mass of 70 kg, they exert a force of
\[70 \times 9.8 =686 N\]
and an added pressure of \[\frac{686}{10^{-3}}=6.86 \times 10^5 Pa\]
.The total pressure is then
\[P_{Total}=3.10 \times 10^5 + 6.86 \times 10^5 =9.96 \times 10^5 Pa\]