## Length of a Line Between Circles Touching

Label the centre of the large circle as O. From the centre of the large circle draw a vertical line to meet the horizontal line at C. The triangle OCB is a right angled triangle, and OC=x=12-10=2cm.

Then

\[CB=\sqrt{10^2-2^2}=\sqrt{96}=\sqrt{16} \sqrt{6}=4 \sqrt{6}cm\]

.Then

\[AB=2CB=8 \sqrt{6}cm\]