There are two very important things to remember about velocity – time graphs.
-
The distance travelled is the area under the graph.
-
The gradient or slope of the graph is equal to the acceleration. If the gradient is negative, then there is a deceleration. We may use the equations(1) or some rearrangement of this equation.
Example. A car starts on a journey. It accelerates for 10 seconds atIt then travels at a constant speed for 50 seconds before coming to rest in a further 4 seconds.
a)Sketch a velocity – time graph.
b)Find the total distance travelled.
c)Find the deceleration when the car is coming to a stop at the end.
d)Find the average speed.
a)We may rearrange (1) to obtainHence we may draw a straight line from (0,0) to (3,30). During the second part the car is travelling at a constant speed of 30m/3. Hence we can draw a straight line to (3,30)+(50,0)=(53,30). During the last part, which takes a further 4 seconds the car comes to a rest, and it's final velocity will be zero. Hence we can draw a straight line to (57,0). We can now draw the velocity time graph.b)Distance travelled = Area under the graph. The graph is a trapezium so use the formula for the area of a trapezium:
c)During the final part of the journey the velocity decreases from 30 to 0 in 4 seconds so
d)