Sums, products, differences and quotients of series converge in the obvious way.
Theorem
If
converges to
and
converges to
then
converges to![]()
Proof: Choose
There is a positive integer
such that if
then
and a positive integer
such that if
then
Let
then if![]()
and
then![]()
Hence
converges to![]()
Theorem
If
converges to
and
converges to
then
converges to![]()
Proof:
Choose
Since
there is a positive integer
such that if
then
a positive integer
such that if
then
and a positive integer
such that if
then
Let
then if![]()
![]()
and ![]()
so take
then
![]()
![]()
Theorem
If
converges to
and
converges to
then
converges to![]()
Proof: Choose
There is a positive integer
such that if
then
and a positive integer
such that if
then
Let
then if![]()
and
then![]()
Hence
converges to![]()
Theorem
If
converges to
and
converges to
then
converges to![]()
Proof: Choose
Since
converges, it is bounded so there exists
such that
for all
Let
There is a positive integer
such that if
then
and a positive integer
such that if
then
Let
then if![]()
and
then![]()
Hence
converges to![]()