Letbe a function on
with
and suppose there exists
such that
for
Then for
maps the open disc
into the the open disc
Proof: Sinceis analytic on
we can write
as a Taylor series about 0.
for
(
since
)
Thenfor
Thus the functionprovides an analytic extension of
from
to
Now apply the maximum principle toon the open disc
where
(we cannot allow
since
– and so
– is not known to be continuous on
This gives
where
for
This inequality holds for allsuch that
we deduce on letting
that
for
Hencefor
so that
for
but since this inequality obviously holds for z=0 we have
for