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Any constant coefficient non homogeneous linear differential equation with initial or boundary conditions can be solved by finding the complementary solution  
\[y_c\]
  of the homogeneous equation and any solution  
\[y_p\]
  of the non homogeneous equation, then the general solution is  
\[y=y_c+y_p\]
. The solution that then be fitted to the initial or boundary conditions to find the values of the arbitrary constants.
Example: Solve the equation  
\[\ddot{y}+4y=3\]
  with initial conditions  
\[y(\pi)=1, \: \dot{y}(\pi)=1\]
.
The homogeneous equation is  
\[\ddot{y}+4y=0\]
  with solution  
\[y_c=Acos 2t+Bsin 2t\]
.
The non homogeneous equation  
\[\ddot{y}+4y=3\]
  has a solution (found by putting  
\[y=C\]
)  
\[y=\frac{3}{4}\]
.
The general solution is then  
\[y=Acos 2t+Bsin2t + \frac{3}{4}\]
.
\[y(\pi)=1 \rightarrow A+ \frac{3}{4} =1 \rightarrow A= 1-\frac{3}{4}= \frac{1}{4}\]

\[\dot{y}(\pi)=2 \rightarrow 2B =2 \rightarrow B= 1\]

Then  
\[y=\frac{1}{4}cos2t+sin 2t+ \frac{3}{4}\]
.