Curvilinear Coordinates

Suppose we have a curvilinear coordinate system with coordinates  
\[(u_1 , u_2 , u_3 )\]

We can express the ordinary Cartesian coordinates in terms of these curvilinear coordinates.
\[x=x(u_1 , u_2 ,u_3 )\]

\[y=y(u_1 , u_2 ,u_3 )\]

\[z=z(u_1 , u_2 ,u_3 )\]

\[\mathbf{r}=\mathbf{r}(u_1 , u_2 ,u_3 )\]

A tangent vector to the

curve is  
\[\frac{\partial \mathbf{r}}{\partial u_1}\]
  and a unit vector tangent to the  
  curve is  
\[ \mathbf{e_1} = \frac{\partial \mathbf{r} / \partial u_1}{ |\partial \mathbf{r} / \partial u_1 |}\]

Similarly, unit vectors tangent to the  
\[u_2 , \; u_3\]
  curves are
\[\mathbf{e_2} = \frac{\partial \mathbf{r} / \partial u_2}{ |\partial \mathbf{r} / \partial u_2 |} , \: \mathbf{e_3} = \frac{\partial \mathbf{r} / \partial u_2}{ |\partial \mathbf{r} / \partial u_3 |}\]

A curvilinear system is said to be orthogonal if the coordinates axes meet at right angles. If the vectors  
\[\mathbf{e_1} , \: \mathbf{e_2} , \: \mathbf{e_3} \]
  are mutually perpendicular the the system is orthogonal and if the dot product of each is 1, the system is also 1, then the system is orthonormal.
\[\mathbf{e_i} \cdot \mathbf{j} = \left\{ \begin{array}{cc} 0 & i \neq j \\ 1 & i=j \end{array} \right. \]

The system is orthonirmal
Also the unit tangent vectors  
\[\mathbf{e_1} , \: \mathbf{e_2} , \: \mathbf{e_3} \]
  are perpendicular to their respective coordinate surfaces so that the vector  
  would be perpendicular to the surface  
\[u_2 = constant\]

Also the system is right handed so that  
\[\mathbf{e_1} \times \mathbf{e_2} = \mathbf{e_3}\]

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