Theorem
Letbe the space of real numbers in the metric spacewith the absolute value metricand let
The closure ofisand the closure of any subsetofis a closed subset of
Proof
LetThe closure ofwrittenis defined aswhere
Since
For each
Henceand
Chooseandthenhence
To prove the closure of any subsetofis a closed subset ofsupposeis not closed thenis not open and there is an elementsuch that for every
Choose
Sinceis open there existssuch that
Sincethensoexists such that
Hence forthere existssuch that Hence contradicting