Theorem
Letbe the space of real numbers in the metric space
with the absolute value metric
and let
The closure ofis
and the closure of any subset
of
is a closed subset of
Proof
LetThe closure of
written
is defined as
where
Since
For each
Henceand
Chooseand
then
hence
To prove the closure of any subsetof
is a closed subset of
suppose
is not closed then
is not open and there is an element
such that for every
Choose
Sinceis open there exists
such that
Sincethen
so
exists such that
Hence forthere exists
such that
Hence
contradicting