Theorem
A metric space
is complete if and only if every nested sequence
of nonempty closed subsets of
with
(diameter tending to 0) has a nonempty intersection so that![]()
Proof
If a complete metric space has every countable nested sequence(
)
of nonempty subsets of
then
is proved here.
Let
be a Cauchy sequence in X.
Define![]()
![]()
![]()
and so on.
Then
and
and all the
are closed, nonempty subsets of
Hence![]()
Let
and take
then there exists
such that for![]()
Hence![]()
For all
hence![]()