Theorem
If
is a compact metric space and
is an open cover of
then there is
such that
for some %alpha for any![]()
That is, a number
exists such that the
- neighbourhood
of any point
is a subset of at least one![]()
The number
is called the Lebesgue number of the cover.
Proof
Since
is a cover of
each
belongs to at least one![]()
Each
is open, hence for each![]()
exists such that
for some![]()
The collection of sets
is an open cover of
and since
is compact, a finite subcover
exists.
The Lebesgue number is defined as
Let
then
Hence
for some![]()