Theorem
Let
where![]()
is continuous if and only if
and
are continuous. Also
is continuous at
if and only if
and
are continuous at![]()
Proof
Suppose that
is continuous at
Since
is continuous at![]()
Suppose now that
and
are continuous at
Let
belong to a subbase of
and let![]()
Set
and we obtain
hence![]()
But
is continuous at t_0 thus![]()
The proof for
is almost identical. Hence
is continuous if and only if
and
are.