Theorem
A function
is continuous if and only if the inverse image of every closed subset of
is closed in![]()
Proof
If
is continuous then![]()
Suppose
is continuous and
is any closed subset of
then
is an open subset of
and
is an open subset of![]()
Suppose for every![]()
is closed in
and
is closed in![]()
Let
be an open subset of
then
is closed in
and
is closed in![]()
![]()
Hence
is an open subset of
and
is continuous.