Theorem
The property of being regular is inherited, so that a subset of aregular space is regular.
Proof
Let
bea regular space and let
bea subspace.
Let
andlet
bea
closedsubset of
suchthat
and
where
isthe closure of
in![]()

Since
isregular, open sets
and
existsuch that![]()
But
and
are
opensubsets of![]()
because
and
Sets
and
aredisjoint because![]()
Also, since
and![]()
isalso regular.