The Chain Rule can be in many different ways. One of the most practical is to find the rate of change of some dimension of a solid when the volume of the solid is changing. For example, a spherical ballon is being blown up and we might want to find the rate of change of the radius, treating the balloon as a sphere, or oil might be poured onto a puddle of oil, and we might want to find the rate of increase of the radius of the oil puddle.
Suppose that a spherically shaped raindrop is falling. As it falls, water condenses on it. The rate of increase of the radius of the raindrop is 0.01 mm/s at a tuime when the radius of the raindrop is 3 mm. What is the rate at which the volume is increasing?
If the raindrop can be treated as a sphere, then the volume of the raindrop is The chain rule may be used in the form
so whenmm,
We are told in the question that the rate of increase ofmm/s, so
mm 3 /s.
Suppose on the other hand that air is being blown into a balloon at the rate of 5 cm 3 /s at a point when the radius of the balloon is 6 cm. Find the rate at which the radius of the ballon is increasing.
Again using the relationshipwithso when r=6 cm,
is the rate at which air is being blown into the balloon, so
cm/s.