\[1+2_3+4+5+6+7+8+9=15\]
There are three rows and three columns so each rown, and each column must add up to 15.
There are only eight possible sums of three numbers to give 15.
1 + 5 + 9 = 15
1 + 6 + 8 = 15
2 + 4 + 9 = 15
2 + 5 + 8 = 15
2 + 6 + 7 = 15
3 + 4 + 8 = 15
3 + 5 + 7 = 15
4 + 5 + 6 = 15
5 appears four times, so must be at the centre of the square, as the sum of the middle row, the middle column and two diagonals
2, 4, 6, 8 each appear three times so must be at the corners, to appear in the sum of a row, diagonal and columns. The square can then only be completed in one way, giving one solution.
Hence, there is at least one solution, namely
\[ \left( \begin{array}{ccc} 2 & 9 & 4 \\ 7 & 5 & 3 \\ 6 & 1 & w8 \end{array} \right) \]
Other solutions can be obtained from this one using the symmetries of a square. The group of symmetries of a square consists of four rotations and four reflections - one horizontal, one vertical and two diagonal.
There are eight solutions in total.