Suppose that
is a function of
and
with partial derivatives
and
These are again functions of
and
and may themselves possess partial derivatives:
![]()
![]()
and![]()
The middle two terms are called the second order partials. There are two mixed partials -
and
The first is obtained by differentiating
first with respect to
then
and the second is obtained by differentiating first with respect to
then![]()
For many functions
In fact if
and it;s partials
and
are all continuous on a set
then
on![]()
If
is a function of three variables
then there are three first partials
and
and nine second partials:![]()
and
![]()
Again the second partials are equal:
![]()
and![]()
provided that
and all it's first and second partial derivatives are continuous.
Example:![]()
![]()
![]()
![]()
Hence![]()