Theorem
Supposeis a map from a metric space
to a metric space
The statements 'is continuous'
and
'for all open setsis open in
Proof
Supposeis continuous and
is an open subset of
Let
then
Sinceis open there exists
such that
Sinceis continuous there exists
such that
Hence (1)
Forexists such that (1) is true hence
is open in
Conversely suppose thatis an open subset of
then
is an open subset of
If
then there exists
is an open subset of
Hence
is an open subset of
Then there exists
such that
or