Theorem
Supposeis a map from a metric spaceto a metric space
The statements 'is continuous'
and
'for all open setsis open in
Proof
Supposeis continuous andis an open subset ofLetthen
Sinceis open there existssuch that
Sinceis continuous there existssuch that
Hence (1)
Forexists such that (1) is true henceis open in
Conversely suppose thatis an open subset ofthenis an open subset ofIf then there existsis an open subset ofHenceis an open subset ofThen there existssuch thator