A subset
of a set
is dense in X if the closure of
is equal to
ie![]()
With this definition the following statements are equivalent.
1.
is dense in![]()
2. If
is a closed set,
is dense in
and
then![]()
3. Each nonempty open set in
contains an element of![]()
The complement
of
has empty interior.
Proof
1. If
is dense in
then
Since
but
since
is closed hence
therefore![]()
2. Let
be an open set with
Then
contradicting 2 because
is closed.
3. Suppose![]()
is open therefore there is a nonempty set
but
hence
and
contains no points of
Hence
contains some element of![]()
4.
hence![]()