Letbe a one to one analytic function whose domain is a region
Then
is analytic on
and
for
Proof: We must show thatfor
and
is continuous on
To prove the first part note that iffor some
then by the local mapping theorem
is many to one near
contradicting that
is one to one on
To prove the second part letand put
We must show that for each there is a
such that
We know thatis an open set by the Open Mapping Theorem so there exists
such that
This implies that